Split TrackApplicationResponse into a Local/External hierarchy
Same treatment as AlbumApplicationResponse, but Track is the cleaner
case: OwnerUserId (local-only) and ExternalId (external-only) are
both genuinely exclusive to one side, so the base carries neither and
is abstract — every real value is one of the two derived types.
TrackApplicationResponse (abstract, shared fields + FromEntity dispatch)
LocalTrackApplicationResponse (+ OwnerUserId)
ExternalTrackApplicationResponse (+ ExternalId)
Hit a real gotcha along the way: the response already had an explicit
Source property, which collides with the "source" discriminator STJ's
polymorphism support injects ("contains property 'source' that
conflicts with an existing metadata property name" — only surfaced at
runtime in the Api integration tests, not at build time). Fixed by
dropping the now-redundant explicit Source field entirely; the
discriminator already serializes the identical "Local"/"YouTube"
value under the same name, so the wire contract is unchanged. Updated
the two call sites that read .Source directly (TrackSearchItemResponse
and a playlist track filter that needed flatMap instead of
filter().map() to keep the narrowing across the chain).
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@@ -3,6 +3,7 @@ using Musify.Application.Contracts;
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using Musify.Application.Services;
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using Musify.Application.Tests.TestSupport;
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using Musify.Application.Tracks;
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using Musify.Application.Tracks.Responses;
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using Musify.Domain.ValueObjects;
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using NSubstitute;
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using Xunit;
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@@ -47,7 +48,8 @@ namespace Musify.Application.Tests.Tracks
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Assert.False(result.IsError);
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Assert.Equal("My Song", result.Value.Title);
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Assert.Equal(user.Id, result.Value.OwnerUserId);
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var localResponse = Assert.IsType<LocalTrackApplicationResponse>(result.Value);
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Assert.Equal(user.Id, localResponse.OwnerUserId);
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await eventBus.Received(1).PublishAsync(Arg.Any<Musify.Application.Events.CreateTrackResourcesEvent>(), Arg.Any<CancellationToken>());
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var stored = await Database.LocalTracks.FindAsync([result.Value.Id], TestContext.Current.CancellationToken);
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